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produce CB to the point of intersection of the 2 cverus say P. join AP & BPArea of the region bounded by the 2 cverus =Area of the half circle with centre B - Area of the region bounded by the line segment PC & the curve PC with centre A= pi/2 *x*x-(Area of te quarter circle with centre A - Area of the right angled triangle PAC=pi*x*x/2-{(pi/4)*root2*x*root2*x} +(1/2)*root2*x*root2*x=pi*x*x/2-pi*x*x/2+x*x=x*x= Area of the square MURALEEDHARAN.C.R GVHSS VATTENAD

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